TIMEOUT
The TRS could not be proven terminating. The proof attempt took 60044 ms.
Problem 1 was processed with processor DependencyGraph (53ms). | Problem 2 remains open; application of the following processors failed [SubtermCriterion (1ms), DependencyGraph (11ms), PolynomialLinearRange4iUR (1334ms), DependencyGraph (7ms), PolynomialLinearRange8NegiUR (12144ms), DependencyGraph (10ms), ReductionPairSAT (timeout)].
f#(a, f(a, f(b, f(x, y)))) | → | f#(a, f(x, y)) | f#(a, f(c, f(x, y))) | → | f#(x, y) | |
f#(a, f(a, f(b, f(x, y)))) | → | f#(a, f(a, f(a, f(x, y)))) | f#(a, f(a, f(b, f(x, y)))) | → | f#(x, y) | |
f#(a, f(a, f(b, f(x, y)))) | → | f#(a, f(a, f(x, y))) |
f(a, f(a, f(b, f(x, y)))) | → | f(b, f(c, f(b, f(a, f(a, f(a, f(x, y))))))) | f(a, f(c, f(x, y))) | → | f(b, f(x, y)) |
Termination of terms over the following signature is verified: f, b, c, a
f#(a, f(a, f(b, f(x, y)))) | → | f#(c, f(b, f(a, f(a, f(a, f(x, y)))))) | f#(a, f(a, f(b, f(x, y)))) | → | f#(a, f(x, y)) | |
f#(a, f(a, f(b, f(x, y)))) | → | f#(b, f(c, f(b, f(a, f(a, f(a, f(x, y))))))) | f#(a, f(c, f(x, y))) | → | f#(x, y) | |
f#(a, f(a, f(b, f(x, y)))) | → | f#(a, f(a, f(a, f(x, y)))) | f#(a, f(a, f(b, f(x, y)))) | → | f#(x, y) | |
f#(a, f(a, f(b, f(x, y)))) | → | f#(b, f(a, f(a, f(a, f(x, y))))) | f#(a, f(a, f(b, f(x, y)))) | → | f#(a, f(a, f(x, y))) | |
f#(a, f(c, f(x, y))) | → | f#(b, f(x, y)) |
f(a, f(a, f(b, f(x, y)))) | → | f(b, f(c, f(b, f(a, f(a, f(a, f(x, y))))))) | f(a, f(c, f(x, y))) | → | f(b, f(x, y)) |
Termination of terms over the following signature is verified: f, b, c, a
f#(a, f(a, f(b, f(x, y)))) → f#(a, f(x, y)) | f#(a, f(c, f(x, y))) → f#(x, y) |
f#(a, f(a, f(b, f(x, y)))) → f#(x, y) | f#(a, f(a, f(b, f(x, y)))) → f#(a, f(a, f(a, f(x, y)))) |
f#(a, f(a, f(b, f(x, y)))) → f#(a, f(a, f(x, y))) |