TIMEOUT
The TRS could not be proven terminating. The proof attempt took 60470 ms.
The following DP Processors were used
Problem 1 was processed with processor DependencyGraph (47ms).
| Problem 2 was processed with processor SubtermCriterion (1ms).
| Problem 3 was processed with processor SubtermCriterion (2ms).
| Problem 4 remains open; application of the following processors failed [SubtermCriterion (0ms), DependencyGraph (1ms), PolynomialLinearRange4iUR (1110ms), DependencyGraph (1ms), PolynomialLinearRange8NegiUR (19617ms), DependencyGraph (1ms), ReductionPairSAT (803ms), DependencyGraph (1ms), SizeChangePrinciple (186ms), ForwardNarrowing (1ms), BackwardInstantiation (1ms), ForwardInstantiation (1ms), Propagation (0ms)].
| Problem 5 was processed with processor SubtermCriterion (0ms).
The following open problems remain:
Open Dependency Pair Problem 4
Dependency Pairs
f#(s(x)) | → | f#(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x)) | → | f(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Problem 1: DependencyGraph
Dependency Pair Problem
Dependency Pairs
f#(s(x)) | → | +#(*(s(x), s(x)), *(s(x), s(s(s(0))))) | | f#(s(x)) | → | f#(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
*#(x, s(y)) | → | +#(x, *(x, y)) | | *#(x, s(y)) | → | *#(x, y) |
f#(s(x)) | → | *#(s(x), s(s(s(0)))) | | f#(s(x)) | → | *#(s(x), s(x)) |
f#(s(x)) | → | -#(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x)))) | | f#(s(x)) | → | *#(s(s(x)), s(s(x))) |
+#(s(x), y) | → | +#(x, y) | | -#(s(x), s(y)) | → | -#(x, y) |
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x)) | → | f(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
The following SCCs where found
f#(s(x)) → f#(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
-#(s(x), s(y)) → -#(x, y) |
Problem 2: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x)) | → | f(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed:
Problem 3: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
-#(s(x), s(y)) | → | -#(x, y) |
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x)) | → | f(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed:
-#(s(x), s(y)) | → | -#(x, y) |
Problem 5: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x)) | → | f(-(+(*(s(x), s(x)), *(s(x), s(s(s(0))))), *(s(s(x)), s(s(x))))) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed: