TIMEOUT
The TRS could not be proven terminating. The proof attempt took 60058 ms.
The following DP Processors were used
Problem 1 was processed with processor DependencyGraph (42ms).
| Problem 2 was processed with processor SubtermCriterion (1ms).
| Problem 3 was processed with processor SubtermCriterion (1ms).
| Problem 4 remains open; application of the following processors failed [SubtermCriterion (0ms), DependencyGraph (0ms), PolynomialLinearRange4iUR (1005ms), DependencyGraph (1ms), PolynomialLinearRange8NegiUR (11132ms), DependencyGraph (1ms), ReductionPairSAT (658ms), DependencyGraph (1ms), SizeChangePrinciple (202ms), ForwardNarrowing (1ms), BackwardInstantiation (44ms), ForwardInstantiation (1ms), Propagation (0ms)].
| Problem 5 was processed with processor SubtermCriterion (0ms).
The following open problems remain:
Open Dependency Pair Problem 4
Dependency Pairs
f#(s(x), y) | → | f#(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x), y) | → | f(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Problem 1: DependencyGraph
Dependency Pair Problem
Dependency Pairs
f#(s(x), y) | → | -#(*(s(x), s(y)), s(*(s(x), y))) | | *#(x, s(y)) | → | +#(x, *(x, y)) |
*#(x, s(y)) | → | *#(x, y) | | f#(s(x), y) | → | *#(s(x), y) |
f#(s(x), y) | → | *#(y, y) | | f#(s(x), y) | → | *#(s(x), s(y)) |
f#(s(x), y) | → | f#(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) | | +#(s(x), y) | → | +#(x, y) |
-#(s(x), s(y)) | → | -#(x, y) |
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x), y) | → | f(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
The following SCCs where found
f#(s(x), y) → f#(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
-#(s(x), s(y)) → -#(x, y) |
Problem 2: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x), y) | → | f(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed:
Problem 3: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
-#(s(x), s(y)) | → | -#(x, y) |
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x), y) | → | f(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed:
-#(s(x), s(y)) | → | -#(x, y) |
Problem 5: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
Rewrite Rules
-(x, 0) | → | x | | -(s(x), s(y)) | → | -(x, y) |
+(0, y) | → | y | | +(s(x), y) | → | s(+(x, y)) |
*(x, 0) | → | 0 | | *(x, s(y)) | → | +(x, *(x, y)) |
f(s(x), y) | → | f(-(*(s(x), s(y)), s(*(s(x), y))), *(y, y)) |
Original Signature
Termination of terms over the following signature is verified: f, 0, s, *, +, -
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed: