MAYBE
The TRS could not be proven terminating. The proof attempt took 10293 ms.
Problem 1 remains open; application of the following processors failed [DependencyGraph (28ms), SubtermCriterion (1ms), DependencyGraph (12ms), PolynomialLinearRange4iUR (530ms), DependencyGraph (7ms), PolynomialLinearRange8NegiUR (4635ms), DependencyGraph (49ms), ReductionPairSAT (4715ms), DependencyGraph (47ms), SizeChangePrinciple (19ms)].
c#(a(a(0, x), y)) | → | c#(c(c(0))) | c#(c(c(y))) | → | c#(a(y, 0)) | |
c#(a(a(0, x), y)) | → | c#(0) | c#(a(a(0, x), y)) | → | c#(c(0)) | |
c#(c(c(y))) | → | c#(c(a(y, 0))) |
c(c(c(y))) | → | c(c(a(y, 0))) | c(a(a(0, x), y)) | → | a(c(c(c(0))), y) | |
c(y) | → | y |
Termination of terms over the following signature is verified: 0, c, a