YES
The TRS could be proven terminating. The proof took 478 ms.
Problem 1 was processed with processor PolynomialLinearRange4iUR (188ms).
app#(app(app(uncurry, f), x), y) | → | app#(app(f, x), y) | app#(app(app(uncurry, f), x), y) | → | app#(f, x) |
app(app(app(uncurry, f), x), y) | → | app(app(f, x), y) |
Termination of terms over the following signature is verified: app, uncurry
app(app(app(uncurry, f), x), y) | → | app(app(f, x), y) |
The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:
app#(app(app(uncurry, f), x), y) | → | app#(app(f, x), y) | app#(app(app(uncurry, f), x), y) | → | app#(f, x) |