MAYBE
The TRS could not be proven terminating. The proof attempt took 56047 ms.
Problem 1 remains open; application of the following processors failed [DependencyGraph (72ms), SubtermCriterion (1ms), DependencyGraph (39ms), PolynomialLinearRange4iUR (1582ms), DependencyGraph (35ms), PolynomialLinearRange8NegiUR (8590ms), DependencyGraph (58ms), ReductionPairSAT (45431ms), DependencyGraph (49ms), SizeChangePrinciple (30ms)].
ap#(ap(ap(foldr, g), h), ap(ap(cons, x), xs)) | → | ap#(ap(foldr, g), h) | ap#(ap(ap(foldr, g), h), ap(ap(cons, x), xs)) | → | ap#(g, x) | |
ap#(ap(f, x), x) | → | ap#(cons, x) | ap#(ap(ap(foldr, g), h), ap(ap(cons, x), xs)) | → | ap#(ap(ap(foldr, g), h), xs) | |
ap#(ap(f, x), x) | → | ap#(f, x) | ap#(ap(f, x), x) | → | ap#(ap(cons, x), nil) | |
ap#(ap(ap(foldr, g), h), ap(ap(cons, x), xs)) | → | ap#(ap(g, x), ap(ap(ap(foldr, g), h), xs)) | ap#(ap(f, x), x) | → | ap#(ap(x, ap(f, x)), ap(ap(cons, x), nil)) | |
ap#(ap(ap(foldr, g), h), ap(ap(cons, x), xs)) | → | ap#(foldr, g) | ap#(ap(f, x), x) | → | ap#(x, ap(f, x)) |
ap(ap(f, x), x) | → | ap(ap(x, ap(f, x)), ap(ap(cons, x), nil)) | ap(ap(ap(foldr, g), h), nil) | → | h | |
ap(ap(ap(foldr, g), h), ap(ap(cons, x), xs)) | → | ap(ap(g, x), ap(ap(ap(foldr, g), h), xs)) |
Termination of terms over the following signature is verified: f, foldr, ap, cons, nil