MAYBE
The TRS could not be proven terminating. The proof attempt took 8002 ms.
The following DP Processors were used
Problem 1 was processed with processor PolynomialLinearRange4iUR (0ms).
| Problem 2 remains open; application of the following processors failed [DependencyGraph (4ms), PolynomialLinearRange4iUR (180ms), DependencyGraph (2ms), PolynomialLinearRange8NegiUR (2333ms), DependencyGraph (2ms), ReductionPairSAT (4955ms), DependencyGraph (1ms), SizeChangePrinciple (9ms)].
The following open problems remain:
Open Dependency Pair Problem 2
Dependency Pairs
f#(f(x, a), a) | → | f#(f(a, f(a, a)), x) | | f#(f(x, a), a) | → | f#(f(f(a, f(a, a)), x), a) |
Rewrite Rules
f(f(x, a), a) | → | f(f(f(a, f(a, a)), x), a) |
Original Signature
Termination of terms over the following signature is verified: f, a
Problem 1: PolynomialLinearRange4iUR
Dependency Pair Problem
Dependency Pairs
f#(f(x, a), a) | → | f#(a, a) | | f#(f(x, a), a) | → | f#(a, f(a, a)) |
f#(f(x, a), a) | → | f#(f(a, f(a, a)), x) | | f#(f(x, a), a) | → | f#(f(f(a, f(a, a)), x), a) |
Rewrite Rules
f(f(x, a), a) | → | f(f(f(a, f(a, a)), x), a) |
Original Signature
Termination of terms over the following signature is verified: f, a
Strategy
Polynomial Interpretation
- a: 0
- f(x,y): 1
- f#(x,y): x
Improved Usable rules
f(f(x, a), a) | → | f(f(f(a, f(a, a)), x), a) |
The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:
f#(f(x, a), a) | → | f#(a, a) | | f#(f(x, a), a) | → | f#(a, f(a, a)) |