TIMEOUT

The TRS could not be proven terminating. The proof attempt took 60001 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (38ms).
 | – Problem 2 was processed with processor SubtermCriterion (1ms).
 | – Problem 3 was processed with processor SubtermCriterion (1ms).
 | – Problem 4 was processed with processor SubtermCriterion (1ms).
 | – Problem 5 remains open; application of the following processors failed [SubtermCriterion (1ms), DependencyGraph (1ms), PolynomialLinearRange4iUR (764ms), DependencyGraph (2ms), PolynomialLinearRange8NegiUR (12257ms), DependencyGraph (2ms), ReductionPairSAT (879ms), DependencyGraph (1ms), SizeChangePrinciple (260ms), ForwardNarrowing (1ms), BackwardInstantiation (1ms), ForwardInstantiation (1ms), Propagation (3ms)].

The following open problems remain:



Open Dependency Pair Problem 5

Dependency Pairs

gcd#(s(x), s(y))gcd#(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))

Rewrite Rules

min(x, 0)0min(0, y)0
min(s(x), s(y))s(min(x, y))max(x, 0)x
max(0, y)ymax(s(x), s(y))s(max(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
gcd(s(x), s(y))gcd(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))gcd(s(x), 0)s(x)
gcd(0, s(y))s(y)

Original Signature

Termination of terms over the following signature is verified: min, max, 0, s, gcd, -


Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

gcd#(s(x), s(y))gcd#(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))min#(s(x), s(y))min#(x, y)
gcd#(s(x), s(y))max#(x, y)gcd#(s(x), s(y))min#(x, y)
max#(s(x), s(y))max#(x, y)-#(s(x), s(y))-#(x, y)
gcd#(s(x), s(y))-#(s(max(x, y)), s(min(x, y)))

Rewrite Rules

min(x, 0)0min(0, y)0
min(s(x), s(y))s(min(x, y))max(x, 0)x
max(0, y)ymax(s(x), s(y))s(max(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
gcd(s(x), s(y))gcd(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))gcd(s(x), 0)s(x)
gcd(0, s(y))s(y)

Original Signature

Termination of terms over the following signature is verified: min, 0, max, s, -, gcd

Strategy


The following SCCs where found

gcd#(s(x), s(y)) → gcd#(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))

min#(s(x), s(y)) → min#(x, y)

max#(s(x), s(y)) → max#(x, y)

-#(s(x), s(y)) → -#(x, y)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

-#(s(x), s(y))-#(x, y)

Rewrite Rules

min(x, 0)0min(0, y)0
min(s(x), s(y))s(min(x, y))max(x, 0)x
max(0, y)ymax(s(x), s(y))s(max(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
gcd(s(x), s(y))gcd(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))gcd(s(x), 0)s(x)
gcd(0, s(y))s(y)

Original Signature

Termination of terms over the following signature is verified: min, 0, max, s, -, gcd

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

-#(s(x), s(y))-#(x, y)

Problem 3: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

max#(s(x), s(y))max#(x, y)

Rewrite Rules

min(x, 0)0min(0, y)0
min(s(x), s(y))s(min(x, y))max(x, 0)x
max(0, y)ymax(s(x), s(y))s(max(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
gcd(s(x), s(y))gcd(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))gcd(s(x), 0)s(x)
gcd(0, s(y))s(y)

Original Signature

Termination of terms over the following signature is verified: min, 0, max, s, -, gcd

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

max#(s(x), s(y))max#(x, y)

Problem 4: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

min#(s(x), s(y))min#(x, y)

Rewrite Rules

min(x, 0)0min(0, y)0
min(s(x), s(y))s(min(x, y))max(x, 0)x
max(0, y)ymax(s(x), s(y))s(max(x, y))
-(x, 0)x-(s(x), s(y))-(x, y)
gcd(s(x), s(y))gcd(-(s(max(x, y)), s(min(x, y))), s(min(x, y)))gcd(s(x), 0)s(x)
gcd(0, s(y))s(y)

Original Signature

Termination of terms over the following signature is verified: min, 0, max, s, -, gcd

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

min#(s(x), s(y))min#(x, y)