YES
The TRS could be proven terminating. The proof took 57 ms.
Problem 1 was processed with processor DependencyGraph (3ms).
mark#(c) | → | a__c# | mark#(f(X)) | → | a__f#(X) | |
a__c# | → | a__f#(g(c)) |
a__c | → | a__f(g(c)) | a__f(g(X)) | → | g(X) | |
mark(c) | → | a__c | mark(f(X)) | → | a__f(X) | |
mark(g(X)) | → | g(X) | a__c | → | c | |
a__f(X) | → | f(X) |
Termination of terms over the following signature is verified: f, g, c, a__c, mark, a__f