YES
The TRS could be proven terminating. The proof took 50 ms.
Problem 1 was processed with processor DependencyGraph (2ms).
terms#(N) | → | sqr#(N) |
terms(N) | → | cons(recip(sqr(N))) | sqr(0) | → | 0 | |
sqr(s) | → | s | dbl(0) | → | 0 | |
dbl(s) | → | s | add(0, X) | → | X | |
add(s, Y) | → | s | first(0, X) | → | nil | |
first(s, cons(Y)) | → | cons(Y) |
Termination of terms over the following signature is verified: 0, s, terms, sqr, dbl, recip, add, first, cons, nil