YES
The TRS could be proven terminating. The proof took 15 ms.
Problem 1 was processed with processor DependencyGraph (2ms).
activate#(n__b) | → | b# | f#(X, X) | → | f#(a, n__b) |
f(X, X) | → | f(a, n__b) | b | → | a | |
b | → | n__b | activate(n__b) | → | b | |
activate(X) | → | X |
Termination of terms over the following signature is verified: f, activate, n__b, b, a