YES
The TRS could be proven terminating. The proof took 250 ms.
Problem 1 was processed with processor BackwardsNarrowing (0ms).
| f#(0, 1, x) | → | f#(x, x, x) |
| f(0, 1, x) | → | f(x, x, x) |
Termination of terms over the following signature is verified: f, 1, 0
| Relevant Terms | Irrelevant Terms |
|---|