YES
The TRS could be proven terminating. The proof took 137 ms.
Problem 1 was processed with processor PolynomialLinearRange4iUR (118ms).
a#(b(a(x))) | → | a#(b(x)) |
a(b(a(x))) | → | b(a(b(x))) |
Termination of terms over the following signature is verified: b, a
There are no usable rules
The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:
a#(b(a(x))) | → | a#(b(x)) |