YES
The TRS could be proven terminating. The proof took 52 ms.
Problem 1 was processed with processor DependencyGraph (3ms).
f#(g(h(x, y)), f(a, a)) | → | f#(y, a) | f#(g(h(x, y)), f(a, a)) | → | f#(h(x, x), g(f(y, a))) |
f(g(h(x, y)), f(a, a)) | → | f(h(x, x), g(f(y, a))) |
Termination of terms over the following signature is verified: f, g, a, h