YES
The TRS could be proven terminating. The proof took 50 ms.
Problem 1 was processed with processor SubtermCriterion (1ms).
a#(b(x)) | → | a#(x) |
a(b(x)) | → | b(b(a(x))) |
Termination of terms over the following signature is verified: b, a
The following projection was used:
Thus, the following dependency pairs are removed:
a#(b(x)) | → | a#(x) |