YES
The TRS could be proven terminating. The proof took 17 ms.
Problem 1 was processed with processor SubtermCriterion (1ms).
dfib#(s(s(x)), y) | → | dfib#(s(x), dfib(x, y)) | dfib#(s(s(x)), y) | → | dfib#(x, y) |
dfib(s(s(x)), y) | → | dfib(s(x), dfib(x, y)) |
Termination of terms over the following signature is verified: dfib, s
The following projection was used:
Thus, the following dependency pairs are removed:
dfib#(s(s(x)), y) | → | dfib#(s(x), dfib(x, y)) | dfib#(s(s(x)), y) | → | dfib#(x, y) |