YES
The TRS could be proven terminating. The proof took 46 ms.
Problem 1 was processed with processor SubtermCriterion (2ms).
+#(*(x, y), +(*(x, z), u)) | → | +#(y, z) | +#(*(x, y), +(x, z)) | → | +#(y, z) | |
+#(*(x, y), +(*(x, z), u)) | → | +#(*(x, +(y, z)), u) | +#(x, +(y, z)) | → | +#(+(x, y), z) | |
+#(x, +(y, z)) | → | +#(x, y) |
+(x, +(y, z)) | → | +(+(x, y), z) | +(*(x, y), +(x, z)) | → | *(x, +(y, z)) | |
+(*(x, y), +(*(x, z), u)) | → | +(*(x, +(y, z)), u) |
Termination of terms over the following signature is verified: *, +
The following projection was used:
Thus, the following dependency pairs are removed:
+#(*(x, y), +(*(x, z), u)) | → | +#(y, z) | +#(*(x, y), +(x, z)) | → | +#(y, z) | |
+#(*(x, y), +(*(x, z), u)) | → | +#(*(x, +(y, z)), u) | +#(x, +(y, z)) | → | +#(+(x, y), z) | |
+#(x, +(y, z)) | → | +#(x, y) |