YES

The TRS could be proven terminating. The proof took 57 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (5ms).
 | – Problem 2 was processed with processor SubtermCriterion (0ms).

Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

f#(f(X))b#(f(X))f#(a(g(X)))b#(X)
f#(f(X))f#(X)f#(f(X))f#(a(b(f(X))))

Rewrite Rules

f(f(X))f(a(b(f(X))))f(a(g(X)))b(X)
b(X)a(X)

Original Signature

Termination of terms over the following signature is verified: f, g, b, a

Strategy


The following SCCs where found

f#(f(X)) → f#(X)

Problem 2: SubtermCriterion



Dependency Pair Problem

Dependency Pairs

f#(f(X))f#(X)

Rewrite Rules

f(f(X))f(a(b(f(X))))f(a(g(X)))b(X)
b(X)a(X)

Original Signature

Termination of terms over the following signature is verified: f, g, b, a

Strategy


Projection

The following projection was used:

Thus, the following dependency pairs are removed:

f#(f(X))f#(X)