YES
The TRS could be proven terminating. The proof took 214 ms.
Problem 1 was processed with processor PolynomialLinearRange4iUR (186ms).
f#(g(X)) | → | f#(f(X)) | f#(g(X)) | → | f#(X) |
f(g(X)) | → | g(f(f(X))) | f(h(X)) | → | h(g(X)) |
Termination of terms over the following signature is verified: f, g, h
f(h(X)) | → | h(g(X)) | f(g(X)) | → | g(f(f(X))) |
The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:
f#(g(X)) | → | f#(f(X)) | f#(g(X)) | → | f#(X) |