YES
The TRS could be proven terminating. The proof took 24 ms.
Problem 1 was processed with processor DependencyGraph (3ms).
f#(a) | → | g#(a) | g#(b) | → | f#(b) | |
g#(b) | → | b# |
g(b) | → | f(b) | f(a) | → | g(a) | |
b | → | a |
Termination of terms over the following signature is verified: f, g, b, a