YES
The TRS could be proven terminating. The proof took 19 ms.
Problem 1 was processed with processor SubtermCriterion (1ms).
f#(g(x, y), f(y, y)) | → | f#(g(y, x), y) |
f(g(x, y), f(y, y)) | → | f(g(y, x), y) |
Termination of terms over the following signature is verified: f, g
The following projection was used:
Thus, the following dependency pairs are removed:
f#(g(x, y), f(y, y)) | → | f#(g(y, x), y) |