NO
The TRS could be proven non-terminating. The proof took 266 ms.
The following reduction sequence is a witness for non-termination:
f#(a) →* f#(a)Problem 1 was processed with processor DependencyGraph (5ms). | Problem 2 remains open; application of the following processors failed [SubtermCriterion (0ms), DependencyGraph (2ms), PolynomialLinearRange4iUR (63ms), DependencyGraph (1ms), PolynomialLinearRange8NegiUR (60ms), DependencyGraph (2ms), ReductionPairSAT (53ms), DependencyGraph (2ms), SizeChangePrinciple (3ms), ForwardNarrowing (0ms), BackwardInstantiation (1ms), ForwardInstantiation (1ms), Propagation (1ms)].
f#(a) | → | f#(a) | f#(a) | → | a# |
f(a) | → | f(a) | a | → | b |
Termination of terms over the following signature is verified: f, b, a
f#(a) → f#(a) |