The TRS could be proven terminating. The proof took 22 ms.
Problem 1 was processed with processor SubtermCriterion (0ms).
| f#(g(x)) | → | f#(x) |
| f(g(x)) | → | g(g(f(x))) | f(g(x)) | → | g(g(g(x))) |
Termination of terms over the following signature is verified: f, g
The following projection was used:
Thus, the following dependency pairs are removed:
| f#(g(x)) | → | f#(x) |