YES
The TRS could be proven terminating. The proof took 55 ms.
Problem 1 was processed with processor SubtermCriterion (1ms).
f#(f(x)) | → | f#(x) |
f(f(x)) | → | g(f(x)) |
Termination of terms over the following signature is verified: f, g
The following projection was used:
Thus, the following dependency pairs are removed:
f#(f(x)) | → | f#(x) |