TIMEOUT
The TRS could not be proven terminating. The proof attempt took 60016 ms.
The following DP Processors were used
Problem 1 was processed with processor DependencyGraph (53ms).
| Problem 2 was processed with processor SubtermCriterion (2ms).
| Problem 3 remains open; application of the following processors failed [SubtermCriterion (0ms), DependencyGraph (5ms), PolynomialLinearRange4iUR (363ms), DependencyGraph (3ms), PolynomialLinearRange8NegiUR (2644ms), DependencyGraph (4ms), ReductionPairSAT (2332ms), DependencyGraph (4ms), SizeChangePrinciple (72ms), ForwardNarrowing (1ms), BackwardInstantiation (1ms), ForwardInstantiation (3ms), Propagation (1ms)].
The following open problems remain:
Open Dependency Pair Problem 3
Dependency Pairs
cond2#(false, x, y) | → | cond1#(gr(x, 0), p(x), y) | | cond1#(true, x, y) | → | cond2#(gr(x, y), x, y) |
cond2#(true, x, y) | → | cond1#(gr(x, 0), y, y) |
Rewrite Rules
cond1(true, x, y) | → | cond2(gr(x, y), x, y) | | cond2(true, x, y) | → | cond1(gr(x, 0), y, y) |
cond2(false, x, y) | → | cond1(gr(x, 0), p(x), y) | | gr(0, x) | → | false |
gr(s(x), 0) | → | true | | gr(s(x), s(y)) | → | gr(x, y) |
p(0) | → | 0 | | p(s(x)) | → | x |
Original Signature
Termination of terms over the following signature is verified: cond2, 0, s, p, false, true, gr, cond1
Problem 1: DependencyGraph
Dependency Pair Problem
Dependency Pairs
cond1#(true, x, y) | → | gr#(x, y) | | cond2#(false, x, y) | → | cond1#(gr(x, 0), p(x), y) |
cond2#(false, x, y) | → | p#(x) | | cond1#(true, x, y) | → | cond2#(gr(x, y), x, y) |
gr#(s(x), s(y)) | → | gr#(x, y) | | cond2#(false, x, y) | → | gr#(x, 0) |
cond2#(true, x, y) | → | gr#(x, 0) | | cond2#(true, x, y) | → | cond1#(gr(x, 0), y, y) |
Rewrite Rules
cond1(true, x, y) | → | cond2(gr(x, y), x, y) | | cond2(true, x, y) | → | cond1(gr(x, 0), y, y) |
cond2(false, x, y) | → | cond1(gr(x, 0), p(x), y) | | gr(0, x) | → | false |
gr(s(x), 0) | → | true | | gr(s(x), s(y)) | → | gr(x, y) |
p(0) | → | 0 | | p(s(x)) | → | x |
Original Signature
Termination of terms over the following signature is verified: cond2, 0, s, p, true, false, gr, cond1
Strategy
The following SCCs where found
cond2#(false, x, y) → cond1#(gr(x, 0), p(x), y) | cond1#(true, x, y) → cond2#(gr(x, y), x, y) |
cond2#(true, x, y) → cond1#(gr(x, 0), y, y) |
gr#(s(x), s(y)) → gr#(x, y) |
Problem 2: SubtermCriterion
Dependency Pair Problem
Dependency Pairs
gr#(s(x), s(y)) | → | gr#(x, y) |
Rewrite Rules
cond1(true, x, y) | → | cond2(gr(x, y), x, y) | | cond2(true, x, y) | → | cond1(gr(x, 0), y, y) |
cond2(false, x, y) | → | cond1(gr(x, 0), p(x), y) | | gr(0, x) | → | false |
gr(s(x), 0) | → | true | | gr(s(x), s(y)) | → | gr(x, y) |
p(0) | → | 0 | | p(s(x)) | → | x |
Original Signature
Termination of terms over the following signature is verified: cond2, 0, s, p, true, false, gr, cond1
Strategy
Projection
The following projection was used:
Thus, the following dependency pairs are removed:
gr#(s(x), s(y)) | → | gr#(x, y) |