YES
The TRS could be proven terminating. The proof took 55 ms.
Problem 1 was processed with processor DependencyGraph (6ms).
p#(f(f(x))) | → | q#(f(g(x))) | q#(f(f(x))) | → | p#(f(g(x))) | |
q#(g(g(x))) | → | p#(g(f(x))) | p#(g(g(x))) | → | q#(g(f(x))) |
p(f(f(x))) | → | q(f(g(x))) | p(g(g(x))) | → | q(g(f(x))) | |
q(f(f(x))) | → | p(f(g(x))) | q(g(g(x))) | → | p(g(f(x))) |
Termination of terms over the following signature is verified: f, g, q, p