MAYBE
The TRS could not be proven terminating. The proof attempt took 271 ms.
Problem 1 was processed with processor DependencyGraph (5ms). | Problem 2 remains open; application of the following processors failed [SubtermCriterion (0ms), DependencyGraph (3ms), PolynomialLinearRange4iUR (0ms), DependencyGraph (2ms), PolynomialOrderingProcessor (0ms), DependencyGraph (2ms), PolynomialLinearRange4 (97ms), DependencyGraph (1ms), ReductionPairSAT (35ms), DependencyGraph (2ms), SizeChangePrinciple (56ms), BackwardsNarrowing (1ms), BackwardInstantiation (timeout), BackwardInstantiation (0ms), ForwardInstantiation (1ms), BackwardInstantiation (2ms), ForwardInstantiation (1ms), Propagation (0ms)].
f#(X, X) | → | h#(a) | g#(a, X) | → | f#(b, X) | |
h#(X) | → | g#(X, X) |
h(X) | → | g(X, X) | g(a, X) | → | f(b, X) | |
f(X, X) | → | h(a) | a | → | b |
Termination of terms over the following signature is verified: f, g, b, a, h
f#(X, X) | → | h#(a) | g#(a, X) | → | f#(b, X) | |
f#(X, X) | → | a# | h#(X) | → | g#(X, X) |
h(X) | → | g(X, X) | g(a, X) | → | f(b, X) | |
f(X, X) | → | h(a) | a | → | b |
Termination of terms over the following signature is verified: f, g, b, a, h
Context-sensitive strategy:
μ(T) = μ(b) = μ(a) = μ(a#) = ∅
μ(f) = μ(g) = μ(f#) = μ(h#) = μ(g#) = μ(h) = {1}
f#(X, X) → h#(a) | g#(a, X) → f#(b, X) |
h#(X) → g#(X, X) |