YES
The TRS could be proven terminating. The proof took 15 ms.
Problem 1 was processed with processor DependencyGraph (6ms).
U01#(c, x) | → | T(x) | g#(x) | → | U11#(x, x) | |
f#(x) | → | U01#(x, x) | U11#(c, x) | → | T(x) |
f(x) | → | U01(x, x) | U01(c, x) | → | x | |
g(x) | → | U11(x, x) | U11(c, x) | → | x | |
a | → | b | a | → | c |
Termination of terms over the following signature is verified: f, g, b, c, a
Context-sensitive strategy:
μ(b) = μ(c) = μ(a) = μ(a#) = μ(T) = ∅
μ(f) = μ(g) = μ(f#) = μ(U11#) = μ(g#) = μ(U01) = μ(U11) = μ(U01#) = {1}