YES

The TRS could be proven terminating. The proof took 100 ms.

The following DP Processors were used


Problem 1 was processed with processor DependencyGraph (5ms).
 | – Problem 2 was processed with processor PolynomialLinearRange4 (75ms).

Problem 1: DependencyGraph



Dependency Pair Problem

Dependency Pairs

f#(b)a#f#(b)f#(a)
a#b#a#U21#(b)

Rewrite Rules

bcf(b)f(a)
aU21(b)U21(c)c

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy

Context-sensitive strategy:
μ(T) = μ(b) = μ(c) = μ(a) = μ(b#) = μ(a#) = ∅
μ(f) = μ(f#) = μ(U21#) = μ(U21) = {1}


The following SCCs where found

f#(b) → f#(a)

Problem 2: PolynomialLinearRange4



Dependency Pair Problem

Dependency Pairs

f#(b)f#(a)

Rewrite Rules

bcf(b)f(a)
aU21(b)U21(c)c

Original Signature

Termination of terms over the following signature is verified: f, b, c, a

Strategy

Context-sensitive strategy:
μ(T) = μ(b) = μ(c) = μ(a) = μ(b#) = μ(a#) = ∅
μ(f) = μ(f#) = μ(U21#) = μ(U21) = {1}


Polynomial Interpretation

Standard Usable rules

U21(c)cbc
aU21(b)

The following dependency pairs are strictly oriented by an ordering on the given polynomial interpretation, thus they are removed:

f#(b)f#(a)